Scala algorithm: Compute single-digit sum of digits

Published

Algorithm goal

\(909\) sums to \(18\), which sums to \(9\).

Find the best way to compute it for any positive \(n\), efficiently.

Test cases in Scala

assert(sumOfDigits(0) == 0)
assert(sumOfDigits(2) == 2)
assert(sumOfDigits(8) == 8)
assert(sumOfDigits(10) == 1)
assert(sumOfDigits(16) == 7)
assert(sumOfDigits(32) == 5)
assert(sumOfDigits(64) == 1)
assert(sumOfDigits(101) == 2)
assert(sumOfDigits(109) == 1)
assert(sumOfDigits(128) == 2)
assert(sumOfDigits(256) == 4)
assert(sumOfDigits(512) == 8)
assert(sumOfDigits(999) == 9)
assert(sumOfDigits(1024) == 7)
assert(sumOfDigits(2048) == 5)
assert(sumOfDigits(4096) == 1)

Algorithm in Scala

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Explanation

This involves a bit of mathematics to figure out - but we can get an \(O(1)\) solution here:

The sum of digits of sum of digits... is equal to that digit modulo 9; if we take a number that is composed of digits\(abcd\), which equals \(10^3 \times a + 10 ^ 2 \times b + 10 \times c + d\), and then using %/modulo 9 we get:\(a + b + c + d (\mod 9)\), which is also \(((a + b) (\mod 9) + (c + d) (\mod 9))(\mod 9)\). Combining with a modulo table, you will notice thatindeed for example \(8 + 7 = 15\), and applying modulo 9 on \(15\) gives us \(6\), which is precisely the sum of digits \(1\) and \(5\). (this is © from www.scala-algorithms.com)

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