Find the minimum absolute difference of partitions in an Array:
For example, array \([7,12,21]\) has partitions \((,[12,21])\) and \(([7,12],)\) with sums \((7, 12 + 21 = 33)\) and \((7 + 12 = 19,21)\), thus absolute differences of \(33 - 7 = 26\) and \(21-19=2\), thus minimum absolute difference of \(2\).
Empty partitions (sum \(0\)) are not considered.
This algorithm is similar to 'TapeEquilibrium' on Codility.
Test cases in Scala
Algorithm in Scala
15 lines of Scala (version 2.13), showing how concise Scala can be!
In a more declarative Scala fashion, we should produce for ourselves a collection which contains a type
(Int, Int) to describe the sum of the left partition and the sum of the right partition.
Once we have this collection, we can run the 'absolute' operation on it, and then 'minOption' to find the minimal value of that. (this is © from www.scala-algorithms.com)
To produce this collection, we start from
(0, TotalSum), and then for each element, we add it to the first int, and subtract it from the second int. The result then becomes our collection - this sort of result is achieved with scanLeft and scanRight, and the optimisation with a View.
Scala concepts & Hints
Drop, Take, dropRight, takeRight
Scala's `drop` and `take` methods typically remove or select `n` items from a collection.
The 'Option' type is used to describe a computation that either has a result or does not. In Scala, you can 'chain' Option processing, combine with lists and other data structures. For example, you can also turn a pattern-match into a function that return an Option, and vice-versa!
Pattern matching in Scala lets you quickly identify what you are looking for in a data, and also extract it.
scanLeft and scanRight
Scala's `scan` functions enable you to do folds like foldLeft and foldRight, while collecting the intermediate results
Stack safety is present where a function cannot crash due to overflowing the limit of number of recursive calls.
This function will work for n = 5, but will not work for n = 2000 (crash with java.lang.StackOverflowError) - however there is a way to fix it :-)
In Scala Algorithms, we try to write the algorithms in a stack-safe way, where possible, so that when you use the algorithms, they will not crash on large inputs. However, stack-safe implementations are often more complex, and in some cases, overly complex, for the task at hand.
.viewsyntax creates a structure that mirrors another structure, until "forced" by an eager operation like .toList, .foreach, .forall, .count.